The speed of a projectile at its maximum height is half of its intial speed. The angle of projection is ......... $^o$
$60$
$15$
$30$
$45$
A projectile is thrown in the upward direction making an angle of $60^o $ with the horizontal direction with a velocity of $147\ ms^{-1}$ . Then the time after which its inclination with the horizontal is $45^o $ , is ......... $\sec$
A ball thrown by one player reaches the other in $2$ sec. the maximum height attained by the ball above the point of projection will be about ....... $m$
Given that $u_x=$ horizontal component of initial velocity of a projectile, $u_y=$ vertical component of initial velocity, $R=$ horizontal range, $T=$ time of flight and $H=$ maximum height of projectile. Now match the following two columns.
Column $I$ | Column $II$ |
$(A)$ $u_x$ is doubled, $u_y$ is halved | $(p)$ $H$ will remain unchanged |
$(B)$ $u_y$ is doubled $u_x$ is halved | $(q)$ $R$ will remain unchanged |
$(C)$ $u_x$ and $u_y$ both are doubled | $(r)$ $R$ will become four times |
$(D)$ Only $u_y$ is doubled | $(s)$ $H$ will become four times |
Match the columns
Column $-I$ $R/H_{max}$ |
Column $-II$ Angle of projection $\theta $ |
$A.$ $1$ | $1.$ ${60^o}$ |
$B.$ $4$ | $2.$ ${30^o}$ |
$C.$ $4\sqrt 3$ | $3.$ ${45^o}$ |
$D.$ $\frac {4}{\sqrt 3}$ | $4.$ $tan^{-1}\,4\,=\,{76^o}$ |
For a given angle of the projectile if the initial velocity is doubled the range of the projectile becomes