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3-2.Motion in Plane
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The speed of a projectile at its maximum height is half of its intial speed. The angle of projection is ......... $^o$
A
$60$
B
$15$
C
$30$
D
$45$
(AIPMT-2010)
Solution

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,\,\,Let\,v\,be\,velocity\,of\,projectile\,at\\
{\rm{maximum}}\,{\rm{height}}\,{\rm{H}}{\rm{.}}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,v\, = \,u\cos \theta \\
According\,to\,given\,problem,\,v = \frac{u}{2}\\
\therefore \,\frac{u}{2} = \,u\cos \,\theta \Rightarrow \cos \theta \frac{1}{2} \Rightarrow \theta = {60^ \circ }
\end{array}$
Standard 11
Physics
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