The speed of a projectile at its maximum height is half of its intial speed. The angle of projection is ......... $^o$

  • [AIPMT 2010]
  • A

    $60$

  • B

    $15$

  • C

    $30$

  • D

    $45$

Similar Questions

A projectile is thrown in the upward direction making an angle of $60^o $ with the horizontal direction with a velocity of $147\ ms^{-1}$ . Then the time after which its inclination with the horizontal is $45^o $ , is    ......... $\sec$

A ball thrown by one player reaches the other in $2$ sec. the maximum height attained by the ball above the point of projection will be about ....... $m$

Given that $u_x=$ horizontal component of initial velocity of a projectile, $u_y=$ vertical component of initial velocity, $R=$ horizontal range, $T=$ time of flight and $H=$ maximum height of projectile. Now match the following two columns.

Column $I$ Column $II$
$(A)$ $u_x$ is doubled, $u_y$ is halved $(p)$ $H$ will remain unchanged
$(B)$ $u_y$ is doubled $u_x$ is halved $(q)$ $R$ will remain unchanged
$(C)$ $u_x$ and $u_y$ both are doubled $(r)$ $R$ will become four times
$(D)$ Only $u_y$ is doubled $(s)$ $H$ will become four times

Match the columns

  Column $-I$
    $R/H_{max}$
  Column $-II$
  Angle of projection $\theta $
   $A.$ $1$    $1.$ ${60^o}$
   $B.$ $4$    $2.$ ${30^o}$
   $C.$ $4\sqrt 3$    $3.$ ${45^o}$
   $D.$ $\frac {4}{\sqrt 3}$    $4.$ $tan^{-1}\,4\,=\,{76^o}$

 

For a given angle of the projectile if the initial velocity is doubled the range of the projectile becomes

  • [AIIMS 2011]